Convert float to formatted wxString Topic is solved

[nime]

Hello (I said I'll be back)

I cant find a handy way (without writing code) for converting float number with wx functions to formatted wxString as was in VB6 format (j, "##0.00") or so and older Basics with PRINT USING "##,###,###.##" .

for example:

float j = 1254.325245;
wxString jk = wxString::Format(wxT("%f"),j);

With this code I can get jk as string representation of j like "1254,325245".
I would like to get " 1.254,33", together with leading spaces which varies depending on number.

And second:
How can I get systems decimal separator sign and thousands separator sign?

[TrV]

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wxString::Format(wxT("%.2f"), j);

More information: http://www.cplusplus.com/reference/clib ... io/printf/

AFAIK, there is no simple way to display thousand separators.

[nime]

Yes I see, this works for printf.
Can I get it to string?

Like this:

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 wxString jk = wxString::Format(wxT("%10d %.2f"),j);

I get weird (incorrect) result...

[upCASE]

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 wxString jk = wxString::Format(wxT("%10d %.2f"),j);

I get weird (incorrect) result...

Sure.
In your case wxString::Format() expects a decimal and a float, but you only pass in "j" as the decimal. The float is missing, hence the "unexpected", yet to be expected, behavior.

[TrV]

As upCASE says:

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wxString jk = wxString::Format(wxT("%.2f"), j);

and

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wxString jk = wxString::Format(wxT("%10d %.2f"), k, j);

work.

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wxString jk = wxString::Format(wxT("%10d %.2f"), j);

is incorrect.

[nime]

Hm,
Yes it works with little issue.

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float j = .325245;
int k = 1254;
wxString jk = wxString::Format(wxT("%10d%.2f"), k, j);

I get result 12540,33 instead of 1254.33
Btw, how to easy crash number to decimal and float?
In Basic I will do :
l=1254.325245
k=FIX(l)
j=l-k

Now I need some time to "cache" this and read about.
Seems that is everything possible to get with this.
Actually, only thousands (and may be million) characters missing.
Is here also some provided trick?
I didnt find nothing useful regarding this reading about printf.

[TrV]

Hm,
Yes it works with little issue.

Code: Select all

float j = .325245;
int k = 1254;
wxString jk = wxString::Format(wxT("%10d%.2f"), k, j);

I get result 12540,33 instead of 1254.33

Is the problem about , (comma) or . (dot) ?
Otherwise, ".33" is not a number. "0.33" is.
If you really need to "erase" the "0", use wxString methods.

Btw, how to easy crash number to decimal and float?
In Basic I will do :
l=1254.325245
k=FIX(l)
j=l-k

Now I need some time to "cache" this and read about.
Seems that is everything possible to get with this.

"crash" numbers???
Please precise what type is l, k and j, what is FIX() and what you want to achieve.
VB is not a typed programming language. C++ is.

Actually, only thousands (and may be million) characters missing.
Is here also some provided trick?
I didnt find nothing useful regarding this reading about printf.

I've already answered.

[nime]

Decimal point was typo.

l, k and j can be single, long or double.
Depends how is declared in scope.

Dim l as long, k as long, j as long
l=1254.325245
k=FIX(l) 'result = 1254
j=l-k 'result = 0.325245 (Basic allow and .325245)

I am not sure what is typed language but if this is types of data that is in Basic also important. Othervise errors occured. Without knowing them you cant work.

I still didnt catch how I can get my favourite 1.254,33 from 1254.325245 cause we come to 12540,33.
But you give me enough important informations.
I will try now to finish alone.

Thanks to all which helps.

[TrV]

Dim l as long, k as long, j as long
l=1254.325245
k=FIX(l) 'result = 1254
j=l-k 'result = 0.325245 (Basic allow and .325245)

"l" cannot definitely be "long" in C++ because "long" is a shortcut for "long integer".

In C++ one has to write:

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double l=1254.325245;
int k = (int)l; // decimal part is removed
double j = l - k;

Hm,
Yes it works with little issue.

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float j = .325245;
int k = 1254;
wxString jk = wxString::Format(wxT("%10d%.2f"), k, j);

I get result 12540,33 instead of 1254.33

I still didnt catch how I can get my favourite 1.254,33 from 1254.325245 cause we come to 12540,33.

How can you expect to have one number whereas you're using 2??? It didn't make any sense to me.

If the idea is to have separated integer and decimal parts of one floating point number and recombine them later, then just add integer and decimal parts to make one and only one number.

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float j = .325245;
int k = 1254;
wxString jk = wxString::Format(wxT("%.2f"), k + j);

[nime]

OK, TrV, thanks a lot.
int k = (int)l we write like Dim k as integer: k = cint(l), FIX is another story.

Now I simply have to read and try various situations with formatting. I am not sure that I know explain what I need at start but we comme wery close. Printf will be also useful for printing to files ko keep numers aligned with fixed fonts.

I like those C++ every day double than yesterday what mean that I advancing with big steps. Because my level of knowledge is not hard multiplying with 2.

And all of this is extremelly interesting for me.

[TrV]

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int k = (int)l;

() is cast operator. It's a very important operator in C++ (and OOP in general).

I would strongly advise you to learn C basics, then C++ basics. These things are really important to know and master before doing things more complex.

[nime]

Yes, you are right.
Thats exactly what I'm trying to do.
I read much these days.